next up previous
Next: The Low-Energy Theory of Up: PHYS 560: Lectures During Previous: Chiral Symmetry and Isospin

Protons and Neutrons

Given the previous and somewhat technical discussion about QCD, lets look at what we know exists in nature. We know that the lightest spin ${1\over 2}$ strongly interacting particles that can be made in the laboratory are the proton and neutron. The proton has mass $M_p~=~938.27231~{\rm MeV}$, and $M_n~=~939.56563~{\rm MeV}$ There are other properties that have been measured, and can be found in the particle data group compilation[3]. There you can find, for the proton

    $\displaystyle M_p~=~938.27231\pm 0.00023~{\rm MeV}\qquad {\rm Mass}$  
    $\displaystyle \mu_p~=~2.79284739\pm 0.00000006 \mu_N\qquad {\rm Magnetic\ Moment}$  
    $\displaystyle d_p~=~\left(-4\pm 6\right)\times 10^{-4}~{\rm e\ cm}\qquad {\rm Electric\ Dipole\ Moment}$  
    $\displaystyle \overline{\alpha}_p~=~\left(12.1\pm 0.9\right)\times 10^{-4}~{\rm fm}\qquad {\rm Electric\ Polarizability}$  
    $\displaystyle \overline{\beta}_p~=~\left(2.1\pm 0.9\right)\times 10^{-4}~{\rm fm}\qquad {\rm Magnetic\ Polarizability}$  
    $\displaystyle \tau_p > 1.6\times 10^{25}~{\rm yrs}\qquad {\rm Mean\ Lifetime}$  
    $\displaystyle r_p~=~0.862\pm 0.012~{\rm fm}\qquad {\rm Charge\ Radius}
\ \ \ ,$ (9)

and for the neutron
    $\displaystyle M_n~=~939.56563\pm 0.00028~{\rm MeV}\qquad {\rm Mass}$  
    $\displaystyle M_n-M_p~=~1.293318\pm 0.000009~{\rm MeV}$  
    $\displaystyle \mu_n~=~-1.9130428\pm 0.0000005 \mu_N\qquad {\rm Magnetic\ Moment}$  
    $\displaystyle d_p < 0.97\times 10^{-25}~{\rm e\ cm}\qquad {\rm Electric\ Dipole\ Moment}$  
    $\displaystyle \overline{\alpha}_p~=~\left(9.8\pm 2.1\right)\times 10^{-4}~{\rm fm}\qquad {\rm Electric\ Polarizability}$  
    $\displaystyle \tau_n~=~ 886.7\pm 1.9~{\rm s}\qquad {\rm Mean\ Lifetime}$  
    $\displaystyle r_n^2~=~-0.119\pm 0.0016~{\rm fm}\qquad {\rm Charge\ Radius}
\ \ \ .$ (10)

Some comments:

1.
The masses of the neutron and proton are very similar, differing at the $10^{-3}$ level. Now, perhaps most fortunately for us, the neutron is slightly heavier than the proton, so that $n\rightarrow pe\overline{\nu}$ in free space, and not $p\rightarrow n\overline{e}\nu$ as would happen if $M_n < M_p$. This scenario would mean that there is no stable hydrogen, and hence a very different universe than the one we live in!
2.
So far an electric dipole for neither the proton $d_p$ nor the neutron $d_n$ has been measured. Such a quantity violates time-reversal invariance, a symmetry that we expect to satisfied in nature to a very high precision. However, the present limit on $d_n$ is close to where some extensions to the standard model of electroweak interactions would may produce a value for $d_n$. The standard model is estimated to give a $d_n$ a few orders of magnitude lower.
3.
It is clear from the fact that both the neutron and proton have non-zero charge radii (for a review see [4]) and also non-zero electric and magnetic polarizabilities, $\overline{\alpha}_p$, $\overline{\alpha}_n$ that the neutron and proton are not point like objects, and have an extended size not so much smaller than $1~{\rm fm}$. A plot of the proton charge form factor can be seen in fig. (2). If the proton wa s apoint object then we would expect the curve to behave like $Q^4$, which clearly it doesn't!

  
Figure: The proton charge form factor $F_1(Q^2)$ multiplied by $Q^4$. Data is from the E136 experiment at SLAC (reproduced without permission).
\includegraphics[width=3in]{/home/savage/Teaching/Class560/Lec560_1/E136F1.ps}



 
next up previous
Next: The Low-Energy Theory of Up: PHYS 560: Lectures During Previous: Chiral Symmetry and Isospin
Martin Savage
1999-10-04