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Next: Chapter 20: Problem 30 Up: Waves and Optics, Solutions Previous: Chapter 20: Problem 24

Chapter 20: Problem 29

Question:        A certain loudspeaker (assumed to be a point source) emits $P = 31.6\ {\rm W}$ of acoustic power. A small microphone of effective cross sectional area $75.2\times 10^{-6}\ {\rm m^2}$ is located a distance $d=194.0\ {\rm m}$ from the loud speaker. Calculate

1.
the sound intensity at the microphone.
2.
the power incident on the microphone.
3.
the amount of energy that impinges on the microphone in $\Delta t =
25.0\ {\rm min}$.

Solution:        

$\displaystyle I = {P\over 4\pi d^2} \ =\ {31.6\over 4\pi (194)^2} \ =\ 6.68\times
10^{-5}\ {\rm W/m^2}
\ \ \ .$     (3)


$\displaystyle P_{\rm mic.}$ = $\displaystyle I . A \ =\ (6.68\times 10^{-5})(75.2\times 10^{-6})\
=\ 5.0\times 10^{-9}\ {\rm W}
\ \ \ .$ (4)


$\displaystyle E_{\rm mic.}$ = $\displaystyle P\ \Delta t \ =\ (5.0\times 10^{-9})(25 60)\ =\
7.54\times 10^{-6}\ {\rm J}
\ \ \ .$ (5)



Martin Savage
1999-01-21