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Next: Chapter 41: Problem 20 Up: Waves and Optics, Solutions Previous: Chapter 41: Problem 5

Chapter 41: Problem 9

Question: Start from Eqs. 5 and 9 (Capter 41) and show that ${\bf E}(x,t)$ and ${\bf B}(x,t)$, the electric and magnetic field components of a plane traveling electromagnetic wave, must satisfy the ``wave equations''

    $\displaystyle {\partial^2\over\partial t^2}{\bf E}~=~c^2 {\partial^2\over\partial
x^2}{\bf E}$  
    $\displaystyle {\partial^2\over\partial t^2}{\bf B}~=~c^2 {\partial^2\over\partial
x^2}{\bf B}
\ \ \ .$ (4)

Solution: We have, from Eq. 5,

    $\displaystyle {\partial\over\partial x}{\bf E}~=~-{\partial\over\partial
t}{\bf B}$  
    $\displaystyle {\partial\over\partial x}\left[ {\partial\over\partial x}{\bf E}~=~-{\partial\over\partial
t}{\bf B}\right]$  
    $\displaystyle {\partial^2\over\partial x^2}{\bf E}~=~- {\partial^2\over\partial t\partial
x}{\bf B}
\ \ \ .$ (5)

We have, from Eq. 9,
    $\displaystyle {\partial\over\partial x}{\bf B}~=~-{1\over c^2}{\partial\over\partial
t}{\bf E}$  
    $\displaystyle {\partial\over\partial t}\left[
{\partial\over\partial x}{\bf B}~=~-{1\over c^2}{\partial\over\partial
t}{\bf E}\right]$  
    $\displaystyle {\partial^2\over\partial t\partial x}{\bf B}~=~-{1\over
c^2}{\partial^2\over\partial t^2}{\bf E}
\ \ \ .$ (6)

Combining these relations we find
    $\displaystyle {1\over c^2}{\partial^2\over\partial t^2}{\bf E}~=~ {\partial^2\over\partial
x^2}{\bf E}
\ \ \ ,$ (7)

and similarly for the magnetic field.


next up previous
Next: Chapter 41: Problem 20 Up: Waves and Optics, Solutions Previous: Chapter 41: Problem 5
Martin Savage
1999-01-27